`2.4+4.7+6.10+....(n-1) terms=`

2.4 + 4.7 + 6.10+ …. upto (n-1) terms=

3.6+4.7+5.8+.....+(n-2) terms =

2 . 4+4 . 6+6 . 8+... to n terms =

(1)/(1 . 4 . 7)+(1)/(4 .7 . 10)+(1)/(7 . 10 . 13)+.. . to n terms =

Prove by mathematical induction that 1.4+4.7+7.10+…. up to n terms =n(3n^(2)+3n-2)

The number of terms common between the series 1+ 2 + 4 + 8..... to 100 terms and 1 + 4 + 7 + 10 +... to 100 terms is

Let S=1/(1.4)+1/(4.7)+1/(7.10)+.....+ n terms observe the following lists

Find the sum of the series : (1)/(1.4)+(1)/(4.7)+(1)/(7.10)+.... to n terms.

Let S=(1)/(1.4)+(1)/(4.7)+(1)/(7.10)+....+n terms observe the following lists