If `1/(2xx4)+1/(4xx6)+1/(6xx8)+...n terms = (kn)/(n+1)`then `k=`

If (1)/(2 xx 4) + (1)/(4 xx 6) + (1)/(6 xx 8) + …… n terms = (kn)/(n +1) then k is equal to

If (1)/( 2 xx 4) + (1)/( 4 xx 6) + (1)/( 6 xx 8) + …. N terms = (kn)/( n+1) then k=

1/2xx 5/4 + 6/8 xx 10/9

Find the sum to n terms of the series 1//(1xx2) + 1//(2xx3) + 1//(3xx4) + cdots + 1//n(n+1).

Simplify : (1/2xx1/4)+\ (1/2xx\ 6)

If (1 + 2 + 3 + 4 + 5 +………..upto n terms) / ( 1xx2 + 2xx3 + 3xx4 + 4xx5 + …. upto n terms) = 3/22 Find the value of n

Prove that 6^(1/2)xx6^(1/4)xx6^(1/8)...oo=6

Evaluate int_(0)^(1) xlog(1+x)dx and hence show that, (1)/(1xx3)-(1)/(2xx4)+(1)/(3xx5)-(1)/(4xx6)+..=(1)/(4)