Let R be the set of real numbers and `f : R -> R` be defined by, `f(x)=x^3+1` then find `f^(-1)(x)`

Let R be the set of real numbers and f:R to R be defined by f(x)=x^(2)+2 , then the set f^(-1)(11 le x le 27) is -

Let R be the set of real numbers and f:R to R be defined by f(x)=2x^(2)-5x+6 , then the value of f^(-1)(2) is -

Let RR be the set of all real numbers and f : R to R be given by f(x) = 3 x^(2) +1 then the set f^(-1) ([1,6]) is -

Let R be the set of real numbers and f:R rarr R be given by,f(x)=x^(2)+2. Find f^(-1){11,16}

R is the set of real numbers,If f:R rarr R is defined by f(x)=sqrt(x) then f is

If f:R->R be defined by f(x)=x^2+1 , then find f^(-1)(17) and f^(-1)(-3) .

Let R be the set of all real numbers and f : R rarr R be given by f(x) = 3x^(2) + 1 . Then the set f^(-1) ([1, 6]) is

Let f: R->R be defined as f(x)=x^2+1 . Find: f^(-1)(10)

Let f: R->R be defined as f(x)=x^2+1 . Find: f^(-1)(10)