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s 3) ol-') ving 2017 JULY SET-A [21] Calculate the cell emf and AG for the cell reaction at 25°C or the cell : Zn(s) I Zn2+(0.0004M) Il Cd2+(0.2M)! Cd (s) Eº values at 25°C: Zn2+ 1 Zn =-0.763 V Cd2+ 1 Cd = -0.403V F = 96500 C, R = 8.314 J K-1 mor! (Marks 4) int: Apply Formula No. 7, 8, and 10] -0.41V; AG=-79.13 KJ mol']

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Calculate the cell e.m.f. and DeltaG for the cell reaction at 25^(@)C for the cell: Zn_((s))|Zn^(2+)(0.004M)||Cd^(2+)(0.2M)|Cd_((s)) E^(@) values at 25^(@)C,Zn^(2+)//Zn=-0.763V Cd^(+2)//Cd=-0.403V F=96,500,R=8.314JK^(-1)mo"le"^(-1) .

Calculate the cell e.m.f. and DeltaG for the cell reaction at 298K for the cell. Zn(s) | Zn^(2+) (0.0004M) ||Cd^(2+) (0.2M)|Cd(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.763 V, E_(Cd^(+2)//Cd)^(@) = - 0.403 V at 298K . F = 96500 C mol^(-1) .

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Calculate the cell e.m.f. and Delta G for the cell reaction at 298 K for the cell. Zn(s)|Zn^(2+)(0.0004 M)|| Cd^(2+)(0.2 M)| Cd(s) Given E_(Zn^(2+)//Zn)^(@)=-0.763 V,E_(cd^(2+)//cd)^(@)=-0.403 V " at "298 K, F=96500 C " mol"^(-1) .

Calculate the cell emf and triangle_(r)G^(@) for the cell reactin at 25^(@)C Zn(s)|Zn^(2+)(0.1M)||Cd^(2+)(0.01M)|Cd(s) (given E_(Zn^(2+)//Zn)^(@)=-0.763V,E_(Cd^(2+)//Cd)^(@)=-0.403V 1F=96500Cmol^(-1),R=8.314JK^(-1)mol^(-1)]