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(90^(@)-theta)cot theta+cos^(2)25^(@)+co...

(90^(@)-theta)cot theta+cos^(2)25^(@)+cos^(2)65^(@))/(27^(@)tan63^(@))=(2)/(3)

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Without using trigonometric tables,find the value of the following expression: (sec(90-theta)*cos ec theta tan(90-theta)cot theta+cos^(2)25+cos^(2)65)/(3tan27^(@)*tan63^(@))

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(tan(90^@-theta) cot theta)/(cosec^2 theta)-cos^2 theta=0

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