Home
Class 12
CHEMISTRY
The resistance of a 0.01N solution of an...

The resistance of a `0.01N` solution of an electroyte was found to 210 ohm at `298K` using a conductivity cell with a cell constant of `0.88 cm^(-1)`. Calculate specific conductance and equilvalent conductance of solution.

Promotional Banner

Similar Questions

Explore conceptually related problems

The resistance of a 0.01 N solution of an electrolyte was found to 210 ohm at 25^(@)C using a conductance cell with a cell constant 0.88 cm^(-1) . Calculate the specific conductance and equivalent conductance of the solution.

The resistance of a 0.01 N solution of an electrolyte was found to 210 ohm at 25^(@)C using a conductance cell with a cell constant 0.88 cm^(-1) . Calculate the specific conductance and equivalent conductance of the solution.

The resistance of a 0.01 N solution of an electrolyte was found to 210 ohm at 25^(@)C using a conductance cell with a cell constant 0.88 cm^(-1) . Calculate the specific conductance and equivalent conductance of the solution.

The resistance of a 0.01 N solution of an electrolyte was found to 210 ohm at 25^(@)C using a conductance cell with a cell constant 0.88 cm^(-1) . Calculate the specific conductance and equivalent conductance of the solution.

The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0. 88cm^(-1) . The value of equivalent conductance of solution is

The resistance of 0.01 N solution of an electrolyte waw found to be 210 ohm at 298 K, when a conductivity cell with cell constant 0.66 cm^(-1) is used. The equivalent conductance of solution is:

The resistance of 0.01N solution of an electrolysis is 210 Omega at 298 K with a cell constant of 0.88 cm^(-1) . Calculate the conductivity and equivalent conducitivty of the solution.

The resistance of 0.01N solution of an electrolysis is 210 Omega at 298 K with a cell constant of 0.88 cm^(-1) . Calculate the conductivity and equivalent conducitivty of the solution.

The resistance of a 0.01 N solution of an electrolyte AB at 328 K is 100 ohm. The specific conductance of the solution is (cell constant =1 cm^(-1) ) :