Home
Class 12
CHEMISTRY
The decomposition of dimethyl ether lead...

The decomposition of dimethyl ether leads to the formation of `CH_(4),H_(2),` and `CO` and the reaction rate is given by
Rate `=k[CH_(3)OCH_(3)]^(3//2)`
The rate of reaction is followed by increase in the pressure in a closed vessel , so the rate can also be expressed in terms of the partial pressure of dimethyl either, `i.e., `
Rate `=k[p_(CH_(3)OCH_(3))]^(3//2)`
If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant ?

Promotional Banner

Similar Questions

Explore conceptually related problems

The decomposition of dimethyl ether leads to the formation of CH_(4) , H_(2) and CO and the reaction -rate is given by Rate k[CH_(3)OCH_(3)]^(3//2) . The rate of reaction is followed by increase in pressure in a closed vessel , so the rate can also be expressed in terms of the partial pressure of dimethyl ether , i.e., Rate =k[P_(CH_(3)OCH_(3))]^(3//2) . If the pressure is measured in bar and time in minutes , then what are the units of rate and rate constants ?

The decomposition of dimethyl ether leads to the formation of CH_4, H_2 and CO and the reaction rate is given by rate = k [CH_(3) OCH_(3) ]^(3//2) . The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e. rate =k (P_(CH_3 OCH_3) )^(3//2) . If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant?

The decomposition of dimethyl ether leads to the formation of (CH)_(4) and (H)_(2) and (CO) and the reaction rate is given by Rate =(k)[(CH)_(3) (OCH)_(3)]^(3 / 2) The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e., Rate= (k)P (C H)_(3) (OCH)_(3)^(3 / 2) If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

The decomposition of dimethyl ether leads to the formation of CH_4, H_2 and CO and the reaction rate is given by Rate = k [CH_3OCH_3]^(3/2) . The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e., Rate= k (P_(CH_3OCH_3 )^(3/2) If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

The decomposition of dimethyl ether leads to the formation of CH_(4) , H_(2) and CO and the reaction rate is given by the expression: rate = k[CH_(3)COOH_(3)]l^(3//2) The rate of reaction is followed by increase in pressure in a close vessel and the rate can also be expressed in terms of partial pressure of dimethyl ether: rate = k[CH_(3)OCH_(3)]^(3//2) The rate of reaction is followed by increase in a close vessel and the rate can also be expressed in terms of partial pressure of dimethyl ether: rate = k[pCH_(3)OCH_(3)]^(3//2) If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant?

The rate expression for the decomposition of dimethyl ether in terms of partial pressures is given as Rate =k (pCH_(3) O CH_(3)) ^(3//2) . If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant ?