[" a coil having "L=2mH," current flow through it is "1=t^(2)e^(-t)" then the time at which "],[2" sec."],[" ent through the coil varies according to graph "]

For a coil having L=4 mH , current flow through it is I=t^3.e^(-t) then the time at which emf becomes zero

Current through the coil varies according to graph then induced emf v/s time graph is

A circular coil 'A' has a radius R and the current flowing through it is I.Another circular coil 'B' has a radius 2R and if 2I is the current flowing through it then the magnetic fields at the centre of the circular coil are in the ratio of

Self-inductance of a coil is 2mH, current through this coil is, I=t^(2)e^(-t) (t = time). After how much time will the induced emf be zero?

Self-inductance of a coil is 2mH, current through this coil is, I=t^(2)e^(-t) (t = time). After how much time will the induced emf be zero?

The self induction of an inductor L = 2mH, and the current through it follows the equation i = e^-t t^2 , then the time at which emf becomes zero

The magnetic flux through a coil varies with time t as follows: phi_(t) = (8t^(3) - 6t^(2) + t - 5) Wb What is the induced current through the coil at t = 4 s, given that the resistance of the coil is 10 Omega and the magnetic flux through the coil is perpendicular to its plane?

The magnetic flux through a coil is varying according to the relation phi=(4t^(2)+2t-5)Wb , t measured in seconds. Calculate the induced current through the coil at t = 2s, if the resistance of the coil is 5Omega .

Current (i) passing through a coil varies with time t as i=2t^(2) . At 1 s total flux passing through the coil is 10 Wb. Then