There is an error of `0.2%` in measurment of the redius of a sphere. Find the percentage error in its
(i) volume, (ii) surface.

The error in the measurement of radius of a sphere is 0.4%. The percentage error in its volume is

If there is an error of 0.1% in the measurement of the radius of a sphere, find approximately the percentage error in the calculation of the volume of the sphere.

If there is an error of 0.1% in the measurement of the radius of a sphere, find approximately the percentage error in the calculation of the volume of the sphere.

If an error of (1/10)% is made in measuring the radius of a sphere, the percentage error in volume is

If the percentage error in the radius of a sphere is a , find the percentage error in its volume.

If there in and error of (1)/(10) % in the measurement of the radius of a sphere, find approximately the percentage error in the calculation of the volume of the sphere.

If the radius of sphere is 3 cm. If an error of 0.03 cm is made in measuring the radius of the sphere, then the percentage error in its surface area is

The error in the measurement of the radius of a sphere is 0.2%. What is the percentage error in the measurement of its surface area?