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A hydrogen like atom (atomic number Z) i...

A hydrogen like atom (atomic number Z) is in a higher excited state of quantum number 'n'. This excited atom can make a transition to the first excited state by emitting a photon of energy 27.2eV. Alterna-tively the atom from the same excited state can make a transition to second excited state by emitting a photon of energy 10.20 eV. The value of n and z are given (Ionization energy of hydrogen atom is 13.6eV) 1) n=6 and z= 3 2 ) n=3 and z=6 3) n=8 and z=4 4) n=4 and z=8

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A hydrogen like atom (atomic number Z) is in a higher excited state of quantum number 'n' this excited atom can make a transition to the first excited state by emitting a photon of first 27.2eV . Alternatively the atom from the same excited state can make a transition of energy 10.20eV the value of n and z are given (ionization energy of hydrogen atom is 13.6eV)

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A hydrogen like atom (atomic number z ) is in a higher excited state of quantum number n . This excited atom can make a transition to the first excited state by successively emitting two photons of energies 10.2 eV and 17.0 eV respectively. Alternatively the atom from the same excited state can make a transition to the second excited state by successively emitting 2 photons of energy 4.25 eV and 5.95 eV respectively. Determine the value of (n+z)

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