Given that `T` stands for time and `l` stands for the length of simple pendulum . If `g` is the acceleration due to gravity , then which of the following statements about the relation `T^(2) = ( l// g)` is correct?

Given that T stands for time period nd 1 stands for the length of simple pendulum. If g is the acceleration due to gravity, then which of the following statements about the relation T^(2)=(l)/(g) is correct ? (I) It is correct both dimensionally as well unmerically (II) It is neither dimensionally correct nor numerically (III) It is dimensionally correct but not numerically (IV) It is numerically correct but not dimensionally

Given that T stands for time period nd 1 stands for the length of simple pendulum. If g is the acceleration due to gravity, then which of the following statements about the relation T^(2)=(l)/(g) is correct ? (I) It is correct both dimensionally as well unmerically (II) It is neither dimensionally correct nor numerically (III) It is dimensionally correct but not numerically (IV) It is numerically correct but not dimensionally

If 'L' is length of simple pendulum and 'g' is acceleration due to gravity then the dimensional formula for (l/g)^(1/2) is same as that for

If 'L' is length of sample pendulum and 'g' is acceleration due to gravity then the dimensional formula for ((l)/(g))^(1/2) is same that for

The time period T of a simple pendulum depends on length L and acceleration due to gravity g Establish a relation using dimensions.

If the time period of a simple pendulum is T = 2pi sqrt(l//g) , then the fractional error in acceleration due to gravity is