[x-2y-1)^(2)+(4x-3y-4)^(2)+(x-2y-1)(4x-3y-4)=0." How many solution to "(x,y)" with "x" ,y real,does "],[" he equation has? "]

Consider the following equation in x and y : (x-2y-1)^(2)+(4x+3y-4)^(2)+(x-2y-1)(4x+3y-4)=0 How many solutions to (x,y) with x,y real,does the equation have

Consider the following equation in x and y: (x-2y-1)^2 + (4x+3y-4)^2 + (x-2y-1)(4x+3y-4) =0 How many solutions to (x, y) with x, y real, does the equation have

Simplify: (3x+2y)(4x+3y)-(2x-y)(7x-3y)

Simplify: (3x+2y)(4x+3y)-\ (2x-y)(7x-3y)

x-3y=1,3x-2y+4=0

If the circle x^(2)+y^(2)+2x+3y+1=0 cuts x^(2)+y^(2)+4x+3y+2=0 at A and B ,then find the equation of the circle on AB as diameter.

If x,y are real and (x-1)^(2)+(y-4)^(2)=0 then the value of x^(3)+y^(3) is

Verify that y = e^(-2x) is a solution of the differential equation y'' + 4y'' - 3y' - 2y = 0 .

Verify that y = e^(-2x) is a solution of the differential equation y''' + 4y'' + 3y' - 2y = 0 .