Two resistors of `10 Omega` and `20 Omega` and an ideal inductor of `10 H` are connected to a `2 V` battery as shows in Fig. key `K` is inserted at time `t = 0`. The initial `(t = 0)` and final `(t rarr oo)` currents through the battery are

Two resistors of 2 Omega and 4 Omega and ideal inductor of 4H are connected to a 12V battery as given in the diagram.The steady current through the battery is

Two resistors of 2 Omega and 4 Omega and ideal inductor of 4H are connected to a 12V battery as given in the diagram.The steady current through the battery is

Three resistors 8 Omega , 12 Omega and 6 Omega are connected to a 12 V battery as shown in Fig. below. the current through the 8 Omega resistor,

Three resistors 8 Omega , 12 Omega and 6 Omega are connected to a 12 V battery as shown in Fig. below. the current through the 6 Omega resistor.

Find the current passing through battery at t=0 and t= oo

Two resistors of resistances 10 Omega and 40 Omega are connected with a capacitor of capacitance 0.1 muF and ideal battery of emf 10 V. When switch (S) is closed, then initial current and current in steady state through the battery respectively are

In the circuit shown in Fig. currrent through the battery at t = 0 and t = oo is

In the circuit shown in Fig. currrent through the battery at t = 0 and t = oo is