Find the distance between centre of gravity and centre of mass of a two particle system attached to the ends of a light rod. Each particle has same mass. Length of the rod is R, where R is the radius of earth.

If the mass of moon is (M)/(81) , where M is the mass of earth, find the distance of the point where gravitational field due to earth and moon cancel each other, from the centre of moon. Given the distance between centres of earth and moon is 60 R where R is the radius of earth

If the mass of moon is (M)/(81) , where M is the mass of earth, find the distance of the point where gravitational field due to earth and moon cancel each other, from the centre of moon. Given the distance between centres of earth and moon is 60 R where R is the radius of earth

If the mass of moon is (M)/(81) , where M is the mass of earth, find the distance of the point where gravitational field due to earth and moon cancel each other, from the centre of moon. Given the distance between centres of earth and moon is 60 R where R is the radius of earth

Find the moment of inertia A of a spherical ball of mass m and radius r attached at the end of a straight rod of mass M and length l , if this system is free to rotate about an axis passing through the end of the rod (end of the rod opposite to sphere).

Find the moment of inertia A of a spherical ball of mass m and radius r attached at the end of a straight rod of mass M and length l , if this system is free to rotate about an axis passing through the end of the rod (end of the rod opposite to sphere).

Find the centre of gravity of a uniform vertical rod height = R/3, where R is the radius of Earth. The lower end of the rod is touching the surface of the Earth.

Statement-1 : The centre of mass of a two particle system lies on the line joining the two particles, being closer to the heavier particle. Statement-2 : Product of mass of one particle and its distance from centre of mass is numerically equal to product of mass of other particle and its distance from centre of mass.

A ring of mass m and radius R has four particles each of mass m attached to the ring as shown in figure. The centre of ring has a speed v_(0). The kinetic energy of the system is

A uniform rod of length L lies on a smooth horizontal table. A particle moving on the table strikes the rod perpendicularly at an end and stops. Find the distance travelled by the centre of the rod by the time it turns through a right angle. Show that if the mass of the rod is four times that of the particle, the collision is elastic