Ionic equilibrium occurs when the rate at which ions are produced equals the rate at which they are consumed, resulting in a constant concentration of ions in solution.
Ionic equilibrium involves the balance between the concentrations of ions in a solution. This concept is essential in understanding how ions interact and maintain a stable environment in aqueous solutions.
Example: In a solution of acetic acid (CH3COOH), an equilibrium is established between the dissociated ions CH3COO- and H+ and the undissociated acetic acid.
Electrolytes vs. Nonelectrolytes:
Degree of Dissociation:
Characteristics:
Examples:
Dissociation Reactions:
Characteristics:
Examples:
Ionization Reactions:
Key Points:
The degree of ionisation (or dissociation) is the fraction of the total number of molecules that ionise (dissociate) into constituent ions in a solution.
The value of the degree of dissociation (α) depends on the following factors:
According to Ostwald, the degree of dissociation (α) of a weak electrolyte is inversely related to the square root of the solution's molar concentration.
Let K be the dissociation constant and C be the molar concentration of the solution.
The relationship is given by Ostwald's Dilution Law:
This law indicates that as the concentration C decreases (i.e., the solution is diluted), the degree of dissociation 𝛼 increases. This is particularly applicable to weak electrolytes, which do not fully dissociate in solution.
For a weak electrolyte, the dissociation constant KC can be expressed in terms of the degree of dissociation 𝛼 and the concentration 𝐶:
However, for very dilute solutions (where α is much less than 1), this simplifies to:
𝐾≈𝐶𝛼2
Thus, rearranging gives:
This simplified version of Ostwald's Dilution Law demonstrates the inverse relationship between the degree of dissociation and the square root of the molar concentration.
Ka represents the dissociation constant of an acid and Kb represents the dissociation constant of a base. The relationship between Ka and Kb is:
Ka × Kb = Kw = 1.0×10−14 ,where Kw is the ion-product constant of water.
Arrhenius Acid: A substance that furnishes hydrogen ions (H⁺) in an aqueous solution.
Example:
Arrhenius Base: A substance that furnishes hydroxide ions (OH⁻) in an aqueous solution.
Example:
H2O + H2O ↔ OH− + H3O+
Acid1 Base2 Base1 Acid2
CH3COOH + H2O ↔ CH3COO−+H3O+
Na++2H2O ↔ NaOH+H3O+
Cl−+H2O ↔ HCl + OH−
NH3 + H2O ↔ NH4+ + OH−
Acid1 Base2 Base1 Acid2
HCl ↔ H++Cl−
C6H5NH2+H+↔C6H5NH3 +
H2O+Al(OH)3↔Al+3(𝑎𝑞)+4H2O
Lewis extended the Bronsted concept to include the following:
The acid strength is defined by its pH:
pH = −log[H+]
The strength of a base is defined by its pOH:
pOH = −log[OH−]
The relationship between pH and pOH is:
pH + pOH =14
A buffer solution maintains its pH relatively stable when small quantities of strong acid or base are introduced. It is also called reserve acidity or basicity, demonstrating buffer action.
Features:
By using the Henderson-Hasselbalch equation, the pH of a buffer solution can be determined
Where: A- is the concentration of the conjugate base. HA is the concentration of the acid.
For a primary buffer (weak base + conjugate acid), the pOH is calculated as:
Where: B− is the concentration of the base. BH is the concentration of the conjugate acid.
When acids react with bases, salts are generated. Upon ionization in solution, the ions of these salts may subsequently interact with water, resulting in the formation of acidic, basic, or neutral solutions depending on the properties of the ions involved.
Common Ion Effect
When equilibrium establishes between an ionic compound and its ions, adding a common ion will shift the equilibrium to consume that ion, according to Le Chatelier’s principle.
The common ion effect is used in:
Isohydric solutions are those where the concentration of common ions(e.g.,OH−−ions in Ca(OH)2 and Ba(OH)2 solutions) is the same. When mixed, the degree of dissociation of either electrolyte does not change.
Solubility: The maximum amount of a substance that dissolves in a fixed amount of a solvent at a specific temperature.
For an ionic compound XY that dissociates in water:
The solubility product (Ksp) is expressed as:
Ionic Product (I.P.): It is the product of the ions' concentrations in the solution.
Ques 1. In the reaction equilibrium P + Q ↔ R + S, what will happen to the concentrations of P, Q, and S if the concentration of R is increased?
Ans When the concentration of R is increased in the reaction equilibrium P + Q ↔ R + S, the system will respond according to Le Chatelier's Principle. This principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change. Equilibrium constant of the reaction can be shown as:
If the concentration of product is increased then the concentration of other components changes which decreases the concentration of R and vice – versa. Thus, increasing the concentration of R shifts the equilibrium to the left, leading to an increase in the concentrations of P and Q and a decrease in the concentration of S.
Ques 2. Write the relationship between molar Solubility (S) and solubility product Ksp for PbI2
Ans The relationship between molar solubility (𝑆) and the solubility product (Ksp) for lead(II) iodide(PbI2):
Dissociation Equation can be written as: PbI2(s)↔Pb2+(aq)+2I−(aq)
Ksp expression: Ksp = [Pb2+][I−]2
Molar solubility(𝑆): [Pb2+] = S
[I−] = 2S
Substituting the values Ksp = S⋅(2S)2 = 4S3
(Session 2025 - 26)