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An ideal spring with spring - constant ...

An ideal spring with spring - constant `K` is bung from the colling and `a` block of mass `M` is attached to its lower end the mass is released with the spring initally unstetched . Then the maximum exlemsion in the spring is

A

`(4Mg)/(K) `

B

`(2Mg)/(K) `

C

`(Mg)/(K) `

D

`(Mg)/(4K) `

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Verified by Experts

The correct Answer is:
B
(b) The shown situation can also be looked upon as the decreses is the gaviational potental energy of spring mass system is equal to the gain in spring elastic poential energy
`Mgx = (1)/(2) kr^(2) , x = (2Mg)/(k)`
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