A uniform chain of length `L` and mass `M` is tying on a smoth table and one third of its length is banging vertically down table the edge of the table if g is acceleration the to gravity , the work required to pull the hanging part on the table is

Options

A. `MgL`
B. `MgL//3`
C. MgL//9`
D. MgL//18`

Answer

D

Explanation

(d) The hanging part of the chain which is to be palled up can be consdered as a point mass situated at the center of the henging part . The equaivalent diagram is drawn .

`= mgh = (M)/(3) xx g xx(L)/(18)`