In the figure (a) and (b) `AC` and `GF` are fixed inclined planes `BC = EF = x` and `AB = DE = y` A small block of mass `M` is rdeased from the point `A` it sides down `AC` and maches `C` with a speed `V_(C) ` The same block is relessed from rest from the point `D` it sides down `DGF` and reached the point the `F` with `V_(p)` The coefficients of kiletic friction between the block and the sarface `AC` and `DGF` are `mu` colculate `V_(C) ` and `V_(p)`

Answer

B, C

Explanation

(a) K.E at `C = Loss in P.E - work done by friction
`(1)/(2) mv_(F)^(2)= mgy - mu mg cos a DG - mumg cos beta GF`
`(1)/(2)v_(F)^(2) = gy - mu (GM)/(DG) xx DG - mug (FN)/(GF)xx GF`
` :. (1)/(2) v_(F)^(2) = gy - mug (GM + FN)`
`:. V_(p) = sqrt(2g (y -mu x)`

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