A rod of weight `w` is supported by two parallel knife edges `A` and `B` and is in equilibrium in a horizontal position. The knives are at a distance `d` from each other. The centre of mass of the rod is at a distance `x` from `A`.
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The correct Answer is:
D
`R_A + R_B = W` `:. R_A = W-R_B`
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