A smooth sphere A is moving on a frictionless horizontal plane with angular speed `omega` and centre of mass velocity `upsilon`. It collides elastically and head on with an identical sphere B at rest. Neglect friction everywhere. After the collision, their angular speeds are `omega_A and omega_B` respectively. Then
A
`omega_A lt omega_B`
B
`omega_A = omega_B`
C
`omega_A =omega`
D
`omega_B =omega`
Text Solution
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The correct Answer is:
C
(c ) As the spheres are smooth there will be no friction (no torque) and therefore there will be no transfer of angular momentum. Thus A, after collision will remain with its intial angular momentum `i.e., omega_A = omega`
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