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Two solid spheres A and B of equal volum...

Two solid spheres A and B of equal volumes but of different densities `d_A and d_B` are connected by a string. They are fully immersed in a fluid of density `d_F`. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if

A

`d_A lt d_F`

B

`d_B gt d_F`

C

`d_Agtd_F`

D

`d_A+d_B = 2d_F`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

(a,b,c) Let V be the volume of shperes.
For equilibrium of A:
`T + vd_Ag = VD_fg`
`:. T = V_g (d_f- d_A)…..(1)`
`for T gt0, d_f gt d_A or d_Altd_f`
(a) is the correct option
For equilibrium of B:
`T + Vd_fg = Vd_Bg`
`:. T = V_g(d_B - d_f) ...(2)`
`For Tgt 0, d_Bgt d_f`
(b) is the correct option
From (1) & (2) Vg `(d_f - d_A) = Vg(d_B - d_f)`
`:. d_f - d_A = d_B - d_f`
`:. 2d_f = d_A + d_B`
(d) is the correct option.
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