A particle of mass m moves along line PC with velocity v as shown. What is the angular momentum of the particle about P?
A
mvL
B
mvI
C
mvr
D
zero
Text Solution
Verified by Experts
The correct Answer is:
D
(d) Angular momentum (L) =(linear momenutm)xx(perpendicular distance of momentum fro the axis of rotation) =mvxxr [Here r =-0 because the line of =mvxx0 action of momentum passes =0 through the axis of rotation]
Topper's Solved these Questions
ROTATIONAL MOTION
SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise MCQs with one correct answer|1 Videos
MOTION
SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise JEE Main And Advanced|63 Videos
SIMPLE HARMONIC MOTION
SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise JEE Main And Advanced|69 Videos
Similar Questions
Explore conceptually related problems
A particle of mass m moves along line PC with velocity v as shown. What is the angular momentum of the particle about O ?
A particle of mass m moves in the XY plane with a velocity v along the straight line AB. If the angular momentum of the particle with respect to origin O is L_(A) when it is at A and L_(B) when it is at B, then
Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?
A particle of mass m is moving along the line y=b,z=0 with constnat speed v . State whether the angular momentum of particle about origin is increasing. Decreasing or constant.
A particle moves on a straight line with a uniform velocity. The angular momentum of the particles is
A particle mass parallel to x-axis with constant velocity v as shown in the figure. The angular velocity of the particle about the origin O
A particle of mass m is projected with a velocity mu at an angle of theta with horizontal.The angular momentum of the particle about the highest point of its trajectory is equal to :
SUNIL BATRA (41 YEARS IITJEE PHYSICS)-ROTATIONAL MOTION-MCQs with one correct answer
