A body A of mass M while falling wertically downwards under gravity brakes into two parts, a body B of mass `(1)/(3)` M and a body C of mass `(2)/(3)` M. The center of mass of bodies B and C taken together shifts compared to that of body A towards
A
does not shift
B
depends on height of breaking
C
body B
D
body C
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we need to analyze the situation step by step.
### Step-by-Step Solution:
1. **Understanding the Initial Condition**:
- We have a body A of mass M falling vertically under the influence of gravity. The center of mass of body A is at its geometric center.
2. **Division of Body A**:
- Body A breaks into two parts: body B with mass \( \frac{1}{3}M \) and body C with mass \( \frac{2}{3}M \).
3. **Finding the Center of Mass of the System**:
- The center of mass (CM) of a system of particles can be calculated using the formula:
\[
x_{CM} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2}
\]
- In our case, we can consider the position of body A before it breaks apart as the origin (0,0) for simplicity.
4. **Position of Bodies After Division**:
- Let’s assume that at the moment of division, body B moves to position \( x_B \) and body C moves to position \( x_C \). Since we are only interested in the shift of the center of mass, we can analyze the positions relative to the center of mass of body A.
5. **Calculating the New Center of Mass**:
- The new center of mass of bodies B and C after the division can be calculated as:
\[
x_{CM} = \frac{\left(\frac{1}{3}M \cdot x_B\right) + \left(\frac{2}{3}M \cdot x_C\right)}{M}
\]
- Since the center of mass of body A was at the origin, and the division occurs without any external force, the center of mass of the system of B and C will still be at the same point as body A.
6. **Conclusion**:
- Since the center of mass of bodies B and C coincides with the center of mass of body A before and after the division, we conclude that there is no shift in the center of mass of the combined system. Therefore, the center of mass of bodies B and C does not shift compared to that of body A.
### Final Answer:
The center of mass of bodies B and C taken together does not shift compared to that of body A.
To solve the problem, we need to analyze the situation step by step.
### Step-by-Step Solution:
1. **Understanding the Initial Condition**:
- We have a body A of mass M falling vertically under the influence of gravity. The center of mass of body A is at its geometric center.
2. **Division of Body A**:
...
Topper's Solved these Questions
ROTATIONAL MOTION
SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise MCQs with one correct answer|1 Videos
MOTION
SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise JEE Main And Advanced|63 Videos
SIMPLE HARMONIC MOTION
SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise JEE Main And Advanced|69 Videos
Similar Questions
Explore conceptually related problems
A body A of mass M my falling vertically downwards under gravity breaks into two parts, a body B of mass 1/4 M and a body C of mass 3/4 M.The centre of mass of bodies B and C taken together shifts compared to that of body A towards
A body falling vertically downwards under gravity breaks in two parts of unequal masses. The centre of mass of the two parts taken together shifts horizontally towards
A body of mass m has gram specific heat c:
A body A mass m_(1) exerts a force on another body B of mass m_(2) . If the acceleration of B be a_(2) , then the acceleration (in magnitude) of A is
Two bodies of masses m_1 and m_2(
A body of mass m is taken to the bottom of a deep mine. Then
SUNIL BATRA (41 YEARS IITJEE PHYSICS)-ROTATIONAL MOTION-MCQs with one correct answer