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For the given uniform square lamina ABCD...

For the given uniform square lamina ABCD, whose centre is O,

A

`I_(AC) = sqrt2 I_(EF)`

B

`sqrt2I_(AC) = I_(EF)`

C

`I_(AD)= 3I_(EF)`

D

`I_(AC) = I_(EF)`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) By the theorem of perpendicular axes,
`I_z = I_x + I_y or , I_z = 2I_y`
(:. I_x = I_y by symmetry of the figure)`
`:. I_(EF) = (I_z)/(2) …(i)`
Again, by the same theorem
`I_z = I_(AC) + I_(BD) = 2I_(AC)`
(:. I_(AC) = I_(BD) by symmetry of the figure)`

`:.I_(AC) =(I_z)/(2) ...(ii)`
From (i) and (ii), we get `I_(Ef) = I_(AC).
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