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A hoop of radius r and mass m rotating w...

A hoop of radius r and mass m rotating with an angular velocity `omega_0` is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases ot slip?

A

`(romega_0)/(4)`

B

`(romega_0)/(3)`

C

`(romega_0)/(2)`

D

`romega_0`

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) From conservation of angular momentum about any fix
point on the surface,
`mr^2omega_0 = 2mr^2 omega`

`rArr omega = omega_0//2 rArr v = (omega_0r)/(2) [:. V= romega]`
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