A homogeneous solid cylinder of length L(LltH/2), cross-sectional area A/5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L/4 in the denser liquid as shown in the figure. The lower density liquid is open to atmosphere having pressure `P_0`. Then density D of solid is given by
A homogeneous solid cylinder of length L(LltH/2), cross-sectional area A/5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L/4 in the denser liquid as shown in the figure. The lower density liquid is open to atmosphere having pressure `P_0`. Then density D of solid is given by
A
(a) `5/4d`
B
(b) `4/5d`
C
(c) `4d`
D
(d) `d/5`
Text Solution
Verified by Experts
The correct Answer is:
A
Weight of cylinder=Upthrust due to upper liquid+Upthrust due to lower liquid.
`D(A/5xxLxxg)=d(A/5)(3/4L)g+2d(A/5)(L/4)xxg`
`:.D=(5d)/(4)`
`D(A/5xxLxxg)=d(A/5)(3/4L)g+2d(A/5)(L/4)xxg`
`:.D=(5d)/(4)`
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