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A glass tube of uniform internal radius(...

A glass tube of uniform internal radius(r) has a valve separating the two identical ends. Intially, the valve is in a tightly closed position. End 1 has a hemispherical soap bubble or radius r. End 2 has sub-hemispherical soap bubble as shown in figure. Just after opening the valve,

A

(a) air from end 1 flows towards end 2. No change in the volume of the soap bubbles

B

(b) air from end 1 flows towards end 2. Volume of the soap bubble at end 1 decreases

C

(c) no changes occurs

D

(d) air from end 2 flows towards end 1. volume of the soap bubble at end 1 increases

Text Solution

Verified by Experts

The correct Answer is:
B
We know that excess pressure in a soap bubble is inversely proportinal to its radius. The soap bubble at end 1 has small radius as compared to the soap bubble at end 2(given). Therefore excess pressure at 1 is more.

As the value is opened, air flows from end 1 to end 2 and the volume of soap bubble at end 1 decreases.
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