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A 0.1kg mass is suspended from a wire of...

A `0.1kg` mass is suspended from a wire of negligible mass. The length of the wire is 1m and its crosssectional are is `4.9xx10^-7m^2`. If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency `140 rad s^-1`. If the Young's modulus of the material of the wire is `nxx10^9 Nm^-2`, the value of n is

Text Solution

Verified by Experts

The correct Answer is:
D
We know that `omega=sqrt(K/m)` …(i)
Here `Y=(FL)/(Al)impliesF=((YA)/(L))l`
Comparing the above equation with `F=kl` we get
`K=((YA)/(L))` …(ii)
From (i) & (ii), `omega=sqrt((YA)/(ml))`
`:. 140=sqrt((nxx10^9xx4.9xx10^-7)/(0.1xx1)) :. n=4`
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