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Work done in increasing the size of a so...

Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution `=0.03Nm^-1`)

A

(a) `0.2pimJ`

B

(b) `2pimJ`

C

(c) `0.4pimJ`

D

(d) `4pimJ`

Text Solution

Verified by Experts

The correct Answer is:
C
W=Tx change in surface area
`W=2T4pi[(5^2)-(3)^2]xx10^4`
`=2xx0.03xx4pi[25-9]xx10^-4J=0.4pixx10^3J`
`=0.4pimJ`
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