A conducting circular loop of radiius `r` carries a constant current `i`. It is placed in a uniform magnetic field `vec(B)_(0)` such that `vec(B)_(0)` is perpendicular to the plane of the loop . The magnetic force acting on the loop is
A
` ir B_(0)`
B
` 2 pi ir B_(0)`
C
` zero`
D
` pi ir B_(0)`
Text Solution
Verified by Experts
The correct Answer is:
C
The magnetic field is perpendicular to the plane of the paper . Let us consider two diametrically opposite elements . By flemin's left hand rule , on element `AB` the direction of force will be leftwards and the magnitude will be ` dF = I(dl) B sin 90@ = I (dl)B` on element `CD` , the direction of force will be towards right on the plane of the paper and the magnitude will be ` dF = I(dl)B`.
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