A charged particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other . The particle will remove in a
A
straight line
B
circle
C
helix
D
helix
Text Solution
Verified by Experts
The correct Answer is:
A
` F_(E) = q^(E)` ( force due to electric field) ` F_(B) = evB sin theta = q vB sin 0 = 0` ( force due to magnetic field ) Force due to electric field will make the charged particle released from rest to move in the straight line ( that of eletric field ) . Since the force due to magnetic field is zero , therefore , the charged particle will move in a straight line.
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