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Two particles A and B of masses m(A) an...

Two particles `A and B` of masses ` m_(A) and m_(B)` respectively and having the same charge are moving in a plane . The speeds of the particles are ` v_(A) and v_(B)` respectively and the trajectories are as shown in the figure. Then

A

` m_(A) v_(A) lt m_(B) v_(B) `

B

` m_(A) v_(A) gt m_(B) v_(B)`

C

` m_(A) v_(A) lt m_(B) and v_(A) lt v_(B) `

D

` m_(A) = m_(B) and v_(a) = v_(B)`

Text Solution

Verified by Experts

The correct Answer is:
B
KEY COCNCEPT: When a charged particle is moving at right angles to the magnetic field then a force acts on it which behaves as a centripetal force and moves the particle in circular motion .
:. ` (m_(A)v^(2)A)/(r_(A)) = q .v_(A)B :. ( m_(A)v_(A))/(r_(A) = q_(B) `
` (m_(B)v_(B))/(r_(B) = q^(B)`
rArr `(m_(A)v_(A))/(r_(A)) = ( m_(B)v_(B))/(r_(B))`
` r_(A)gt r_(B)`
rArr m_(A)v_(A) gt m_(B) v_(B) `
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Knowledge Check

  • Two particle A and B of masses m_(A) and m_(B) respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are v_(A) and v_(B) respectively and the trajectories are as shown in the figure. Then-

    A
    `m_(A) v_(A) lt m_(B)v_(B)`
    B
    `m_(A)v_(A) gt m_(B) v_(B)`
    C
    `m_(A) lt m_(B) and v_(A) lt v_(B)`
    D
    `m_(A) = m_(B) and v_(A) = v_(B)`

  • Two particles A and B of masses m_(A)andm_(B) respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are v_(A)andv_(B) respectively and the trajectories are as shown in the figure. Then -

    A
    `m_(A)v_(A)ltm_(B)v_(B)`
    B
    `m_(A)v_(A)gtm_(B)v_(B)`
    C
    `m_(A)ltm_(B)andv_(A)ltv_(B)`
    D
    `m_(A)=m_(B)andv_(A)=v_(B)`

  • Two particles A and B of masses m_A and m_B respectively and having the same charge are moving ina plane. A uniform magnetic field exists perependicular to this plane. The speeds of the particles are v_A and v_B respectively and the trajectories are as shown in the figure. Then,

    A
    `m_Av_Altm_Bv_B`
    B
    `m_Av_Agtm_Bv_B`
    C
    `m_Altm_B and v_Altv_B`
    D
    `m_A=m_B and v_A=v_B`

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