A particle of the mass ` m ` and cgharge ` q` moves with a constant velocity `v` along the positive x- direction . It enters a region containing a uniform magnetic field `B` directed along the minimum value of `v` required so that the particle can just enter the region ` xgtb` is
A
`(qbB)/(m)`
B
`(q(b-A) B)/(m)`
C
`(qaB)/(m)`
D
`(q(b+a)B)/(2m)`
Text Solution
Verified by Experts
The correct Answer is:
B
width of the magnetic field region `(b-a)le R`, where 'R' is its radius of curvature inside magnetic field, :. `R = (mv)/(q^(B)) ge( b-a) rArr v_(min) = ((b-a)q^(B))/(m)`
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