A current carrying loop is placed in a uniform magnetic field in four different orientations , I,ii,iii & iv arrange them in the decreasing order of potential Energy`
A
`Igt IIIgtIIgtIV`
B
`Igt IIgt IIIgtIV`
C
`Igt IVgtIIgtIII`
D
`IIIgtIVgtIgtII`
Text Solution
Verified by Experts
The correct Answer is:
A
` U = - vec(-M). Vec(B) = -MB cos theta ` In case I , ` theta = 180@ , U = + MB` In case II , ` theta = 90@, U = 0 ` IN case III , ` theta = actute , U = +ve( less than + MB)` In case IV , ` theta = obtuse , U = - ve` :. IgtIIIgtIIgtIV`.
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