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A current carrying loop is placed in a uniform magnetic field in four different orientations , I,ii,iii & iv arrange them in the decreasing order of potential Energy`



A

`Igt IIIgtIIgtIV`

B

`Igt IIgt IIIgtIV`

C

`Igt IVgtIIgtIII`

D

`IIIgtIVgtIgtII`

Text Solution

Verified by Experts

The correct Answer is:
A

` U = - vec(-M). Vec(B) = -MB cos theta `
In case I , ` theta = 180@ , U = + MB`
In case II , ` theta = 90@, U = 0 `
IN case III , ` theta = actute , U = +ve( less than + MB)`
In case IV , ` theta = obtuse , U = - ve`
:. IgtIIIgtIIgtIV`.
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