Two particle X and Y having equal charge, after being accelerated through the same potential difference enter a region of uniform magnetic field and describe circular paths of radii `R_1 and R_2` respectively. The ratio of the mass of X to that of Y is
A
`(R_(1))//(R_(2))^(1//2)`
B
`(R_(1))//(R_(2))`
C
`(R_(1))//(R_(2))^(2)`
D
`(R_(1))//(R_(2))`
Text Solution
Verified by Experts
The correct Answer is:
C
` KgtE.` of first particle ` = 1/2 m_(1)v_(1)^(2) = qV` ……(i) ` KgtE.` of first particle ` = 1/2 m_(2)v_(2)^(2) = qV` ……(ii) ` R = (sqrt(2 m k))/(q^(B)` Here , ` K , q, B` are equal :. R^(2) prop m` rArr (m_(1))/(m_(2)) = (R_(1)^(2))/(R_(2)^(2))
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