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Two metallic rings A and B identical in ...

Two metallic rings `A` and `B` identical in shape and size but having different resistivities `rho_(A)` and `rho_(B)` are kept on top of two idential solenoids as shown in the figure.When current `I` is switched on in both the solenoids in identical manner, the rings `A` and `B` jump to heights `h_(A)` and `h_(B)` respectively with `h_(A)` gt `h_(B)`. The possible relation(s) between their resistivities and their masses `m_(A)` and `m_(B)` is (are)

A

`rho_(A) gt rho_(B)` and `m_(A) = m_(B)`

B

`rho_(A) lt rho_(B)` and `m_(A) = m_(B)`

C

`rho_(A) gt rho_(B)` and `m_(A) gt m_(B)`

D

`rho_(A) lt rho_(B)` and `m_(A) lt m_(B)`

Text Solution

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The correct Answer is:
B, D
when current `I` is switched on in both the solenoids in identical manner , eddy currents are setup in metallic rings `A and B` in such a way that rings `A and B` are repelled.
Given ` h_(A) gt h_(B)`. This shows that eddy currents produced in `A` are greater than in `B`. This is possible when ` rho_(A)lt rho_(B)` ( the rate of change of flux is same in both the rings , therefore induced emf is same).
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