A conductor (shown in the figure) carrying constant current `I` is kept in the `x-y` plane in a uniform magnetic field ` vec(B)`. If ` vec(F)` is the magnitude of the total magnetic force acting on the conductor, then the correct statement(s) is (are)
A
If `vec(B)` is along `hat (z)` , `F prop (L+R)`
B
If `vec(B)` is along `hat (x)` ,F = 0`
C
If `vec(B)` is along `hat (y)` , `F prop (L+R)`
D
If `vec(B)` is along `hat (z)` , `F = 0`
Text Solution
Verified by Experts
The correct Answer is:
A, B, C
` vec(F) = I [(int vec( dl ))xx vec(B)]` If ` vec(B)` is along `z` then ` vec(F)` = I[(2L+ 2R)hat(i) xxB hat (x)]` option ` [A]` is correct If ` vec(B)` is along ` vec(x)` then `vec(F) = I[(2L+ 2R)hat(i) xxB hat (i)] = 0` If `vec(B)` is along ` vec(y)` then ` vec(F) = I[(2L+ 2R)hat(i) xx hat (j)]` Option `(b) and (c)` are also correct
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