:. Magnetic field due to current carrying conductor `P` at point O` is
` B_(1) = (mu_(0))/(4 pi) (i)/(OR)`
directed towards the reader perpendicular to the plane of paper.
Magnetic field due to current carrying conductor `Q` at point `O` is directed towards the reader perpendicular to the plane of paper.
` B_(2) = (mu_(0))/( 4pi) (i)/(OS)`
Magnetic field due to current carrying conductors `L and M` at `O` is zero.
:. Resultant magnetic field at `O`
` B = B_(1) + B_(2)`
( directed towards the reader perpendicular to the plane of paper)
rArr B = (mu_(0))/(4 pi) (i)/(OR)+ (mu_(0))/( 4 pi) (i)/(OS) = (mu_(0))/( 4 pi) i [ (1)/(OR) + (1)/(OS) ]`
` = 10^(-7)xx10xx[(1)/(0.02) + (1)/(0.02)] = 10^(-4) tesla`.
