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The figure shows a circular loop of radi...

The figure shows a circular loop of radius `a` with two long parallel wires `(numbered 1 and 2)` all in the plane of the paper . The distance of each wire from the centre of the loop is `d`. The loop and the wire are carrying the same current `I`. The current in the loop is in the counterclockwise direction if seen from above.
(q) The magnetic fields(B) at `P` due to the currents in the wires are in opposite directions.
(r) There is no magnetic field at `P`.
(s) The wires repel each other.

(4) When `d~~a` but wires are not touching the loop , it is found that the net magnetic field on the axis of the loop . In that case

A

(a) current in wire `1 and wire 2` in the direction `PQ and RS`, respectively and ` h~~a`

B

(b) current in wire `1 and wire 2` in the direction `PQ and SR`, respectively and `h~~a`

C

current in wire `1 and wire 2` in the direction `PQ and SR`, respectively and `h~~1.2 a`

D

current in wire `1 and wire 2` in the direction `PQ and RS`, respectively and `h~~1.2 a`

Text Solution

Verified by Experts

The correct Answer is:
D
Magnetic field due to current carrying loop = Magnetic field due to straight wires
` B = B_(1) cos theta + B_(2) cos theta = 2 B_(!) cos theta `
` (mu_(0)Ia^(2))/(2(a^(2)I +h^(2))^( 3//2)) = 2[ (mu_(0)I)/( 2 pi sqrt(a^(2) +h^(2)))]xx(a)/sqrt(a^(2)+h^(2))`
rArr ` h ~~ 1.2a`
The current is from `P to Q` in wire 1 and from `R to S` in wire 2.
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