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In a thin rectangular metallic strip a c...

In a thin rectangular metallic strip a constant current `I` flows along the positive `x-direction , as shown in the figure. The length , width and thickness of the strip are `l, w and d`, respectively.
A uniform magnetic field `vec(B)` is applied on the strip along the positive `y- direction` . Due to this, the charge carriers experience a net deflection along the `z- direction` . This results in accumulation of charge carriers on the surface `PQRS` ansd apperance of equal and opposite charges on the face opposite to `PQRS`. A potential difference along the `z-direction` is thus developed. Charge accumulation contiues untill the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross- section of the strip and carried by electrons.
Consider two different metallic strips `(1 and 2)` of same dimensions `n_(1) and n_(2)`, repectrively . Strip 1 is placed in magnetic field `B_(1)` and strip 2 is placed in magnetic field `B_(2)` , both along positive ` y- directions`. Then ` V_(1) and V_(2)` are the potential differences developed between `K and M` in strips 1 and 2 , respectively . Assuming that the current `I` is the same for both the strips, the correct option(s) is (are)

A

If `B_(1) = B_(2) and n_(1) = 2n_(2), then V_(2) = 2V_(1)`

B

If `B_(1) = B_(2) and n_(1) = 2n_(2), then V_(2) = V_(1)`

C

If `B_(1) = 2B_(2) and n_(1) = 2n_(2), then V_(2) = 0.5 V_(1)`

D

If `B_(1) = 2B_(2) and n_(1) = 2n_(2), then V_(2) = V_(1)`

Text Solution

Verified by Experts

The correct Answer is:
B

Here
` V prop (B)/(n) rArr (V_(1)n_(1))/(B_(1)) = (V_(2)n_(2))/(B_(2)) ltbr. If ` B_(1) = B_(2) and n_(1) = 2 n_(2) rArr V_(2) = 2V_(1)`
and of `B_(1) = 2 B_(2) and n_(1) = n_(2) rArr V_(2) = 0.5V_(1)`
`A and C `are the correct options.
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