A particle of mass `M` and charge `Q` moving with velocity `vec(v)` describe a circular path of radius `R` when subjected to a uniform transverse magnetic field of induction `B`. The work done by the field when the particle completes one full circle is
A
`((Mv^(2)/( R )) 2 pi R `
B
`zero`
C
`B Q 2 pi R`
D
` B Q v2pi R`
Text Solution
Verified by Experts
The correct Answer is:
B
The workdone, `dW = Fds cos theta` The angle between force and displacement is `90^(@)` . Therefore work done is zero.
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