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A particle of charge -16xx10^(-18) coulo...

A particle of charge `-16xx10^(-18) coulomb` moving with velocity `10 ms^(-1)` along the ` x- axis `, and an electric field of magnitude `(10^(4))//(m)` is along the negative ` z- ais`. If the charged particle continues moving along the ` x- axis` , the magnitude of `B` is

A

`(10^(3) Wb)//(m^(2))`

B

`(10^(5) Wb)//(m^(2))`

C

`(10^(16) Wb)//(m^(2))`

D

`(10^(-3) Wb)//(m^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
The situation is shown in the figure .
`F_(E) = Force due to electric field `
`F_(B) = Force due to magnetic field `
It is given that the charged particle remins moving along `X-axis`( i.e. undeviated). Therefore `F_(B) = F_(E)`
rArr qvB = qE rArr B = (E)/(v) = (10^(4))/(10) = 10^(3) weber//m^(2)`
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  • A particleofcharge -16xx 10^(-18) coulombmoving with velocity 10 m s^(-1) along the x-axis enters a region where a magnetic field B is along the y-axis, and an electric field of magnitude 10^(4) V/m is along the negative z-axis. If the charged particle continues moving along the x-axis, the magnitude of B is

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