Two long conductors, separated by a distance `d` carry current `I_(1) and I_(2)` in the same direction . They exert a force `F` on each other. Now the current in one of them is increased to two times and its direction is reversed . The distance is also increased to `3d`. The new value of the force between them is
A
`-( 2 F)/(3)
B
`( F)/(3)`
C
` - 2 F`
D
`- (F)/(3)`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we will use the formula for the force between two parallel conductors carrying currents. The force per unit length \( F \) between two long parallel conductors carrying currents \( I_1 \) and \( I_2 \) separated by a distance \( d \) is given by:
\[
F = \frac{\mu_0}{4\pi} \cdot \frac{I_1 I_2}{d} \cdot L
\]
where \( \mu_0 \) is the permeability of free space and \( L \) is the length of the conductors.
### Step 1: Identify the initial conditions
- Currents: \( I_1 \) and \( I_2 \)
- Distance: \( d \)
- Force: \( F \)
The initial force can be expressed as:
\[
F = \frac{\mu_0}{4\pi} \cdot \frac{I_1 I_2}{d} \cdot L
\]
### Step 2: Modify the conditions based on the problem statement
- The current in one conductor is doubled and reversed, so:
- New current \( I_1' = -2I_1 \) (the negative sign indicates the direction is reversed)
- The distance is increased to \( 3d \).
### Step 3: Write the new force expression
The new force \( F' \) between the conductors can be calculated using the modified values:
\[
F' = \frac{\mu_0}{4\pi} \cdot \frac{(-2I_1) I_2}{3d} \cdot L
\]
### Step 4: Simplify the new force expression
Substituting the values into the equation:
\[
F' = \frac{\mu_0}{4\pi} \cdot \frac{-2 I_1 I_2}{3d} \cdot L
\]
### Step 5: Relate the new force to the original force
We can express \( F' \) in terms of \( F \):
\[
F' = -\frac{2}{3} \cdot \frac{\mu_0}{4\pi} \cdot \frac{I_1 I_2}{d} \cdot L
\]
This can be rewritten as:
\[
F' = -\frac{2}{3} F
\]
### Conclusion
The new value of the force between the conductors is:
\[
F' = -\frac{2}{3} F
\]
This indicates that the force is repulsive due to the reversal of the current direction.
To solve the problem, we will use the formula for the force between two parallel conductors carrying currents. The force per unit length \( F \) between two long parallel conductors carrying currents \( I_1 \) and \( I_2 \) separated by a distance \( d \) is given by:
\[
F = \frac{\mu_0}{4\pi} \cdot \frac{I_1 I_2}{d} \cdot L
\]
where \( \mu_0 \) is the permeability of free space and \( L \) is the length of the conductors.
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