A current loop `ABCD` is held fixed on the plane of the paper as shown in figure. The arcs `BC( radius = b) and DA ( radius = a)` of the loop are joined by two straight wires `AB and CD` at the origin `O` is 30^(@)`. Another straight thin wire with steady current `I_(1)` flowing out of the plane of the paper is kept at the origin . Due to the process of the current `I_(1)` at the origin:
A
The forcwes on `AD and BC` are zero.
B
The magnitude of the net force on the loop is given by `(I_(1)I)/( 4 pi) mu_(0)[2 ( b-a)+pi//3( a+b)]`
C
The magnitude of the net force on the loop is given by `(mu_(0)II)/( 24 ab) ( b-a)`
D
The forces on `AB and DC` are Zero.
Text Solution
Verified by Experts
The correct Answer is:
A
KEY CONCEPT : `vec(F) = I(vec(l)xxvec(B)) ` The force on `AD and BC` due to corrent `I_(1)` is zero. This is because the directions of current element `Ivec(dl)` and magnetic field `vec(B)` are parallel.
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