A slab of a material of refractive index 2 shown in fig. has a curved surface APB of radius of curvature 10 cm and a plane surface CD. On the left of APB is air and on the right CD is water with refractive indices as given in the figure. An object O is placed at a distance of 15 cm from the pole P as shown. The distance of the final image of O from P, as viewed from the left is......

Answer

C

Explanation

For refraction at APB
`-(mu_2)/(u)+(mu_1)/(v)=(mu_1-mu_2)/R`
`implies (-2)/(-15)+(1)/(v)=(1-2)/(-10)` implies v= -30cm `
implies Image of O will be formed at 30 cm to the right at P.