If `epsilon_0` and `mu_o` are, respectively, the electric permittivity and magnetic permeability of free space, `epsilon` and `mu` the corresponding quantities in a medium, the index of refraction of the medium in terms of the above parameters is….

Explanation

Velocity of light in vacuum `c=(1)/(sqrtmu_0epsilon_0)`
and the velocity of light in a medium `v=(1)/(sqrtmuepsilon)`
`n=(Velocity light in vacuum)/(Velocity light in medium)=`c/v=(1/(sqrtmu_0epsilon_0))/(1/(sqrtmuepsilon))=(sqrtmuepsilon)/(sqrtmu_0epsi_0)`