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In a double slit experiment instead of t...

In a double slit experiment instead of taking slits of equal widths, one slit is made twice as wide as the other. Then, in the interference pattern

A

the intensities of both the maxima and the minima increase

B

the intensity of the maxima increases and the minima has zero intensity

C

the intensity of the maxima decreases and that of the minima increases

D

the intensity of the maxima decreases and the minima has zero intensity

Text Solution

Verified by Experts

The correct Answer is:
A

When slits are of equal width.
`I_maxpropto(a+a)^1(=4a^2)`
`I_minpropto(a-a)^2(=0)`
When one slit's width is twice that of other `(I_1)/(I_2)=(W_1)/(W_2)=(a^2)/(b^2)` `implies (W)/(2W)=(a^2)/(b^2)` ` implies `b= sqrt2a`
:' `I_max propto(a+sqrt2a)^2=(5.8a^2)`
`I_minpropto(sqrt2a-a)^2`=`(=0.17a^2)`
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