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A light beam is travelling from Region I...

A light beam is travelling from Region `I` to `IV` (figure). The refractive index in regionals `I,II,III` and `IV` are `n_0=(n_0)/(2)`(n_0)/(6) and (n_0)/(8)` respectively. The angle of incidence `theta` for which the beam just misses entering region IV is- `

A

`sin^(-1)((3)/(4))`

B

`sin^(-1)((1)/(8))`

C

`sin^(-1)((1)/(4))`

D

`sin^(-1)((1)/(3))`

Text Solution

Verified by Experts

The correct Answer is:
B

For refraction at parallel interfaces
`n_(0)sintheta=(n_(0))/(2)sinalpha=(n_(0))/(6)sinbeta=(n_(0))/(8)sin90degree`
`:'`sin theta=(1)/(8)
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