A parallel bean of light travelling in water (refractie index `=4/3)` is refracted by a spohereical bubble of radius 2 mm situation in water. Assuming the light rays to be paraxial. i. find the position of the image due to refraction at the first surface and the positoin of the final image, and ii draw a ray diagram showing the positions of oth the images.

Explanation

(i) Initially the object is in denser medium and `u=infty` using the formula of refraction at a spherical surface for AB
`-u_(2)/(u)+(mu_(1))/(v)=(mu_(1)-mu_(2))/(R)implies((1-4)/(3))/(2)` `implies` `v=-6mm` NOTE: This is the position of the image due to refraction at the first surface. This image will behave as a virtual object for the refraction at the second surface. `u=-6-4=-10mm`
Again using the formula of refraction at a spherical surface for CD
`-(mu_(1))/(mu^(`))+(mu_(2))/(v^(`))=(+mu_(2)-mu_(1))/(R),-(1)/(10)+((4)/(3)-1)/(-2)``implies``v^(`)=-5mm`.
The is the position of final image.

(ii) Ray diagram.