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An electromagnetic wave of frequency v=3...

An electromagnetic wave of frequency `v=3.0 MHz` passes from vacuum into a dielectric medium with permittivity `epsilon=4.0`. Then

A

wave length is halved and ferquency remains unchanged

B

wave length is doubled and frequency becomes half

C

wave length is doubled and the frequency remains unchanged

D

wave length and frequency both remain unchanged.

Text Solution

Verified by Experts

The correct Answer is:
A

Frequency remains constant during refraction
`v_(med)=(1)/(sqrt(mu_0epsi_0xx4))=(c)/(2)`
`(lamda_(med))/(lamda_(air))=(v_(med))/(v_(air))=(c)/(2)=(1)/(2)`
wavelength is halved and frequency remains unchanged
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